Suggested: (p+1)x^2-6(p+1)x+3(p+9)=0 - find the value of p for which the quadratic equation (p+1)x^2-6(p+1)x+3(p+q)=0 - p(x)=2x3+x2-2x-1 g(x)=x+1 - if p(x)=x2-2√2x+1 then p(2√2) is equal to - p(x)=x3+3x2+3x+1 g(x)=x+2 - p(x)=(x+1)(x-2) x=-1 2 - find the value of p for which the quadratic equation p(x-4)(x-2)+(x-1)^2 - if x-1 is a factor of the polynomial p(x)=x^3+ax^2+2b and a+b=4 - find the value of p for which the quadratic equation (2p+1)x2-(7p+2)x+(7p-3)=0 - p(x)=3x2-1 x=-1/√3 2/√3 - बहुपद p(x)=2x+1 का शून्यक है - p(x)=2x+1 x=1/2 - find a zero of the polynomial p(x)=2x+1 - (x+y)(p+q)2+(x-y)(p-q)2=1 - (p+1)x^2 Browse related:
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